8019 Sable Creek Dr E, Jacksonville, FL 32244 is a single family home on a 13,825 sq feet lot located in Duval County. This home has 4 bedrooms and 2 bathrooms.
| Date | Price |
|---|---|
| 2017-07-10 | $178,000 54.6% |
| 1995-12-12 | $115,100 |
| Year | Property Taxes | Tax Assessment | Homestead Exemption |
|---|---|---|---|
| 2024 | $6,252 78.5% | $339,115 | |
| 2023 | $3,503 9.3% | $225,348 | check |
| 2022 | $3,205 0.8% | $218,785 | check |
| 2021 | $3,181 -8.0% | $212,413 | check |
| 2020 | $3,458 -1.3% | $185,361 | |
| 2019 | $3,504 4.7% | $185,295 | |
| 2018 | $3,347 6.5% | $174,928 | |
| 2017 | $3,141 4.2% | $161,663 | |
| 2016 | $3,015 9.9% | $148,445 | |
| 2015 | $2,743 6.1% | $134,950 | |
| 2014 | $2,585 5.8% | $125,201 | |
| 2013 | $2,444 | $117,240 |
